Let y= (√3).(sinθ)^2+(2sinθcosθ)-(√3).(cosθ)^2
Find the maximum and minimum values of y,and the corresponding general solution of θ at which y attains its maximum and minimum作者: 98102257 時間: 09-6-16 12:16 PM
參考一下
y=-√3[(cos x)^2 - (sin x)^2] + 2 sin x cos x
=-√3 cos 2x + sin 2x
=2 cos(2x-150°)
Therefore the maximum value of y = 2 when cos(2x-150°) = 1
and the minimum value of y = -2 when cos(2x-150°) = -1作者: Naozumi 時間: 09-6-16 11:11 PM