(OB x PA)/2 = (OA x 9)/2 <-- area=area
15PA = 6 x 9
PA = 54/15 = 18/5 unit
6. A,B,C are collinear
so,slope of AB = slope of AC
(2a-a) / (1+2) = (a+1)/(-2-7)
3a + 3 = -9a
a = -1/4
7. let <ABE = <EBC = a , <ACD=<DCB=b.
AB=AC(given)
so, <ABC = < ACB (base angle,isos. tri.)
<DCB = < EBC <--- 2a=2b
BC = BC ( common side)
so,tri. BCE and tri. CBD are congruent.(A.S.A)
so, <BDC=<CEB = 90 degree (corr. angle of cong. tri.)
therefore,CD is an altitude of tri. ABC