if -4 and 2 are the roots of the quadratic equation -2x^2+rx+s=0
find the values of r and s作者: abcdefg111 時間: 10-11-1 05:21 PM
if -4 and 2 are the roots of the quadratic equation -2x^2+rx+s=0
find the values of r and s
put -4 into -2x^2+rx+s
-2(16)-4r+s=0
4r+32=s......1
put 2 into -2x^2+rx+s
-2(4)+2r+s=0
2r+s=8......2
2r+(4r+32)=8
6r=-24
r=-4
s=16