2000FUN論壇

標題: function [打印本頁]

作者: abcdefg111    時間: 11-3-9 09:33 PM     標題: function

Let f:[-1,1]-> [0,兀], f(x) =arc cosx and g: R->R, g(x)=f(cosx)
a) show左g(x) is even and periodic
b)Find g(x) for all x belongs to[0,兀]
hence, sketch the graph of g(x) for all x belongs to [-2兀,2兀]

我想問咩係arc cos(x)?同埋b)點做 thx!
作者: Naozumi    時間: 11-3-10 08:56 AM

arc cosx 即係俾個數 x, 搵番一個角 y pi<= y <=0),令到 cos y = x

所以當 0 <= x <= pi
g(x) = arc cos (cos x)) = x




歡迎光臨 2000FUN論壇 (https://www.2000fun.com/) Powered by Discuz! X1.5.1