probability

kwoklap

P(A) = 0.3
P(B|A) = 0.75
P(B|A') =0.2
P(C|A'∩B) = 0.15
P(C|A∩B) = 0.2
P(C|A∩B') = 0.8
P(C|A'∩B') = 0.9
P(A∩B∩C) = 0.045

find P(B'∩C)
thx

kwoklap

都係冇野la,我計到la
ans : P(C|A'∩B') x  P(B'|A') x P(A')  + P(C|A∩B') x P(B'|A) x P(A) = 0.564

之前我諗個set operation 諗到我仆街, 但係用左tree diagram就好快做到