求解方程(要有step)

caw123456

1. 8分之5(3-x)減2分之x加3 =0

2, 3分之t加1=6分之5t減1 加0.6

3, 5分之2y減1加4分之1加y=1減2分之1減y


快,要交功課!thanks!

雪子秀

1) [5(3-x)/8] - [4(x+3)/8] = 0
    15-5x-4x-12 = 0
    -9x = -3
       x = 1/3
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2) [10(t+1)/30] = [5(5t-1)/30] + [18/30]
    10(t+1) = 5(5t-1) +18
    10t+10 = 25t-5+18
    -15t = 3
         t = -1/5
經驗算後，兩者答案是 4/15
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3) [4(2y-1)/20] + [5(1+y)/20] = 20/20 - [10(1-y)/20]
    4(2y-1)+5(1+y) = 20-10(1-y)
    8y-4+5+5y = 20-10+10y
                 3y = 9
                   y = 3
經驗算後，兩者答案是 2