9(b)
f(x)=(ax+b)(ax+b), f(x)=12
so (ax+b)(ax+b)=12
(ax)(ax)+2abx+b*b=12
2x*2x+2*2*4*x+4*4-12=0
4x*x+16x+4=0
x*x+4x+1=0
x={-4+ square root of [4*4-4(1)(1)]}/2(1)
=(-4+ 2*square root of 3)/2
=-2+square root of 3
or
x={-4- square root of [4*4-4(1)(1)]}/2(1)
=(-4- 2*square root of 3)/2
=-2-square root of 3